Question

log (6x-1) - log (x+4) = log x ecuaciones logaritmicas

Answer 1

Bien, 

Log (6x - 1 ) - Log ( x+ 4 ) = Log x 

Log $( \frac{6x-1}{x+4} )$ = Log x

$\frac{6x-1}{x+4} = x$

6x - 1 = x^2 + 4x 

-x^2 + 2x -1 = 0

- ( x - 1)^2 = 0 

x - 1 = 0 

x = 1

R/ x =1 

Answer 2

Respuesta:

Explicación paso a paso:

Log (6x - 1 ) - Log ( x+ 4 ) = Log x  

Log  = Log x

6x - 1 = x^2 + 4x  

-x^2 + 2x -1 = 0

- ( x - 1)^2 = 0  

x - 1 = 0  

x = 1

R/ x =1