Question

4x+2y+3z=8
3x+4y+2z= -1
2x-y+5z= -3

por el metodo de sarrus por fa <3

Answer 1

4...2...3
3...4...2
2...-1..5=
4...2...3
3...4...2

(4)(4)(5)+(3)(-1)(3)+(2)(2)(2)-(3)(4)(2)-(2)(-1)(4)-(5)(2)(3)=

80-9+8-24+8-30=33

Ese va a ser el denominador que se va a usar:

Primero despejare (x)

8...2...3
-1...4...2
-3..-1...5 =
8...2...3
-1...4...2

(8)(4)(5)+(-1)(-1)(3)+(-3)(2)(2)-(3)(4)(-3)-(2)(-1)(8)-(5)(2)(-1)=

160+3-12+36+16+10=213

213/33= 71/11


Ahora con y

4...8...3
3...-1...2
2...-3...5=
4...8...3
3...-1...2

-20-27+32+6+24-120= -105

-105/33= -35/11


Ahora z

4...2...8
3...4...-1
2...-1...-3 =
4...2...8
3...4...-1

-48-24-4-64-4+18= -126

-126/33= -42/11

Salu2.

Suerte... :)