Question

minimo comun multiplo de 6,12,36 y 3,9,18 y 10,25,50 y 20,40,80

Answer 1

6| 2
3| 3
1 |

12| 2
6| 2
3| 3
1 |

36| 2
18 | 2
9 | 3
3 | 3
1 |

Factores primos 6 = 2 × 3
Factores primos 12 = 2 × 2 × 3
Factores primos 36 = 2 × 2 × 3 × 3

M.C.M ( 6, 12, 36 ) = 2 × 2 × 3 × 3 = 36

3 |3
1 |

9| 3
3| 3
1 |

18| 2
9| 3
3| 3
1 |

Factores primos 3 = 3
Factores primos 9 = 3 × 3
Factores primos 18 = 2 × 3 × 3
M.C.M (3, 9, 18) = 2 × 3 × 3 = 18


10| 2
5 | 5
1 |

25| 5
5 | 5
1 |

50 | 2
25 | 5
5 | 5
1 |

Factores primos 10 = 2 × 5
Factores primos 25 = 5 × 5
Factores primos 50 = 2 × 5 × 5
M.C.M ( 10, 25, 50 ) = 2 × 5 × 5 = 50

20| 2
10 | 2
5 | 5
1 |

40| 2
20| 2
10 | 2
5 | 5
1 |

80| 2
40| 2
20| 2
10 | 2
5| 5
1 |

Factores primos 20 = 2 × 2 × 5
Factores primos 40 = 2 × 2 × 2 × 5
Factores primos 80 = 2 × 2 × 2 × 2 × 5
M.C.M ( 20, 40, 80 ) = 2 × 2 × 2 × 2 × 5 = 80

Answer 2

Respuesta:

Explicación paso a paso:

No entiendo que 6-12-13