Question

Sec β - Cos β !!!!!!!

Answer 1

Primero cambiamos sec(x)

1/cos(x) - cos(x)

[1-cos²(x)]/cos(x)

Cambiamos el 1-cos²(x)

sen²(x)/cosx

[sen(x) × sen(x)] / cos(x)

tg(x)sen(x)