Laepinefrina (adrenalina) una hormona secretada hacia el torrente sanguíneo enmomentos de peligro o tensión contiene: 59.0% en masa de C, 7.1% de H, 26.2% deO y 7.7% de N; PM de cerca de 180 g/mol.?
Respuestas
Respuesta dada por:
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C: 59.0 g/ 12 g/mol = 4.9167 mol
H: 7.1 g/ 1 g/mol = 7.1 mol
O: 26.2 g/16 g/mol = 1.638 mol
N: 7.7 g/ 14 g/mol = 0.55 mol
dividir entre el menor de los resultados
C: 4.9167 mol / 0.55 mol = 9
H: 7.1 mol / 0.55 mol = 13
N: 0.55 mol / 0.55 mol = 1
O. 1.638 mol / 0.55 mol = 3
FE: C9H13NO3
Mm FE
C: 9 x 12 = 108 g/mol
H: 13 x 1 = 13 g/mol
N: 1 X 14 = 14 g/mol
O: 3 x `16 = 48 g/mol
````````````````````````````
Mm= 183 g/mol
n = 180 g/mol / 183 g/mol = 1
FM = (C9H13NO3)₁ = C9H13NO3
``````````````````````````````
Mm = 151 g/mol
H: 7.1 g/ 1 g/mol = 7.1 mol
O: 26.2 g/16 g/mol = 1.638 mol
N: 7.7 g/ 14 g/mol = 0.55 mol
dividir entre el menor de los resultados
C: 4.9167 mol / 0.55 mol = 9
H: 7.1 mol / 0.55 mol = 13
N: 0.55 mol / 0.55 mol = 1
O. 1.638 mol / 0.55 mol = 3
FE: C9H13NO3
Mm FE
C: 9 x 12 = 108 g/mol
H: 13 x 1 = 13 g/mol
N: 1 X 14 = 14 g/mol
O: 3 x `16 = 48 g/mol
````````````````````````````
Mm= 183 g/mol
n = 180 g/mol / 183 g/mol = 1
FM = (C9H13NO3)₁ = C9H13NO3
``````````````````````````````
Mm = 151 g/mol
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