Question

35 pts.!!! Urge, por favor con procedimiento

[ 1/4 + 3/2 (4/5)] ÷ [ 3/4 ( -1/2) -1/6]

[ 5/4 + 14/8 (-2/4)²] ÷ [ 6/6 - 9/2 (-1/3)³]

Answer 1

Hola!

35 pts.!!! Urge, por favor con procedimiento 

[ 1/4 + 3/2 (4/5)] ÷ [ 3/4 ( -1/2) -1/6]

[ 5/4 + 14/8 (-2/4)²] ÷ [ 6/6 - 9/2 (-1/3)³]

$\left[ \dfrac{1}{4}+ \dfrac{3}{2} \left( \dfrac{4}{5}\right)\right]: \left[ \dfrac{3}{4}\left(- \dfrac{1}{2}\right) - \dfrac{1}{6} \right]= \\ \\ \\ \left[ \dfrac{1}{4}+ \dfrac{3*4}{2*5} \right]: \left[ \left(- \dfrac{3*1}{4*2}\right) - \dfrac{1}{6} \right]= \\ \\ \\ \left[ \dfrac{1}{4}+ \dfrac{12}{10} \right]: \left[ \left(- \dfrac{3}{8}\right) - \dfrac{1}{6} \right]= \\ \\ \\ \left[ \dfrac{10+48}{40} \right]: \left[ \dfrac{-9-4}{24} \right]=$

$\left[ \dfrac{58}{40} \right]: \left[ \dfrac{-13}{24} \right]= \dfrac{58*24}{40*(-13) } =\dfrac{1392}{-520 } = \boxed{- \dfrac{174}{65}}$


$\left[ \dfrac{5}{4}+ \dfrac{14}{8}\left( \dfrac{2}{4}\right) ^2\right] :\left[ \dfrac{6}{6}- \dfrac{9}{2}\left( \dfrac{1}{3}\right) ^3\right]= \\ \\ \\ \left[ \dfrac{5}{4}+ \dfrac{14}{8}\left( \dfrac{4}{16}\right)\right] :\left[ \dfrac{6}{6}- \dfrac{9}{2}\left( \dfrac{1}{27}\right)\right]= \\ \\ \\ \left[ \dfrac{5}{4}+ \dfrac{7}{16}\right] :\left[ \dfrac{6}{6}- \dfrac{1}{6}\right]= \dfrac{27}{16} : \dfrac{5}{6}= \dfrac{27*6}{16*5}= \boxed{ \dfrac{81}{40}}$


Espero que te sirva, salu2!!!!