Question

5 ejemplos de binomio al cubo simples porfa

Answer 1

(a + 3)³= a³ + 3(a)²(3) + 3(a)(3)² + (3)³= 27 + 9a² + 27a + 27

(p – q)³ = p³ – 3(p)²(q) + 3(p)(q)² – q³= p³ – 3p²q + 3pq² - q³

(x + 2)³ = x³ + 3(x)²(2) + 3(x)(2)² + 2³= x³ + 6x² + 12x + 8

(a – 3)³ = a³ + 3(a)²(3) + 3(a)(3)²+ (3)³= a³ + 9a² + 27a + 27

(t + 4)³ = t³ + 3(t)²(4) + 3(t)(4)² + (4)³ == t³ + 3(t)²(4) + 3(t)(4)² + (4)³= t³ + 12t² + 48t + 64.
No son tan simples pero espero que te sea util .

Answer 2

a³+9=(a+3) (a²-3a+9)
m³-n³=(m-n )(m²+mn+n²)
27+b³=(3+b) (9-3b+b²)
a³-b³=(a-b) (a²+ab+b² )
9+c³=( 3+c ) ( 9-3c+ c²)