Question

Hola, un favor pueden resolver estos problemas de factorizacion porfavor no puedo y es pra el sabado por la noche
1. x2y – y – zy

2. 7abc – 35abc2

3. 2a4b – 4ab4 – 6a4b4

4. (m + n - 1)x2 + (m + n - 1)x – (m + n - 1)

5. (m2 + n)(x - y) – (m2 + n)(2x + 5y)

6. (x + y)(a + b) + (x + y)(m + n)

7. (x + y + z + w)a5 – (x + y + z + w)(b + c)

8. xy – zy + xt + zt

9. x5 + x3 + x2 + 1

10. ab + bc + xa + xc

Answer 1

1. x²y – y – zy = y(x²-1-z)
2. 7abc – 35abc² = 7abc(1-5c)
3. 2a4b – 4ab4 – 6a4b4 = 2ab(1a³+2b³-3a³b³)
4. (m + n - 1)x2 + (m + n - 1)x – (m + n - 1)
 =(m+n-1)(²+x-1)
5. (m2 + n)(x - y) – (m2 + n)(2x + 5y)= (m²+n)((x-y)-(2x+5y))
(m²+n)(-x-6y)
6. (x + y)(a + b) + (x + y)(m + n)=  (x+y)((a+b)+(m+n))
7. (x + y + z + w)a5 – (x + y + z + w)(b + c)
 =(x+y+z+w)((a5-(b+c))
8. xy – zy + xt + zt =x (y+t)-z(y+t)= (x-z)(y+t)
9. x5 + x3 + x2 + 1 = (x²+1)(x+1)(x².x+1)
10. ab + bc + xa + xc =a (b+x)+c(b+x) = (a+c)(b+x)

                                               .............Kd

Answer 2

Respuesta:

espero que te sirva

Explicación paso a paso:

1. x²y – y – zy = y(x²-1-z)

2. 7abc – 35abc² = 7abc(1-5c)

3. 2a4b – 4ab4 – 6a4b4 = 2ab(1a³+2b³-3a³b³)

4. (m + n - 1)x2 + (m + n - 1)x – (m + n - 1)

=(m+n-1)(²+x-1)

5. (m2 + n)(x - y) – (m2 + n)(2x + 5y)= (m²+n)((x-y)-(2x+5y))

(m²+n)(-x-6y)

6. (x + y)(a + b) + (x + y)(m + n)=  (x+y)((a+b)+(m+n))

7. (x + y + z + w)a5 – (x + y + z + w)(b + c)

=(x+y+z+w)((a5-(b+c))

8. xy – zy + xt + zt =x (y+t)-z(y+t)= (x-z)(y+t)

9. x5 + x3 + x2 + 1 = (x²+1)(x+1)(x².x+1)

10. ab + bc + xa + xc =a (b+x)+c(b+x) = (a+c)(b+x)