Question

formula empírica de 87,5 de nitrógeno 12.5 de hidrógeno

Answer 1

N: 87.5 g/ 14 g/mol = 6.25 mol
H: 12.5 g/ 1 g/mol = 12.5 mol

dividir

N: 6.25 mol / 6.25 mol = 1
H: 12.5 mol / 6.25 mol = 2

FE: NH2