Question

Resuelve radicales semejantes 7/2√11-4/3√7-5/6√11+-9/4+√7

Answer 1

$\frac{7}{2} \sqrt{11}- \frac{4}{3} \sqrt{7}- \frac{5}{6} \sqrt{11}- \frac{9}{4} \sqrt{7}= \\ \\ ( \frac{7}{2} \sqrt{11} }- \frac{5}{6} \sqrt{11})+( }- \frac{4}{3} \sqrt{7}- \frac{9}{4} \sqrt{7})= \\ \\ ( \frac{21-5}{6}) \sqrt{11}+( \frac{-16-27}{12}) \sqrt{7}= \\ \\ \frac{16}{6} \sqrt{11}- \frac{43}{12} \sqrt{7} = \\ \\ \frac{8}{3} \sqrt{11}- \frac{43}{12} \sqrt{7}$