Question

$\sqrt{16x^{2} } + \sqrt{16y^{2} } +5x -3x =0$

Answer 1

√16x^2+16y^2+5x-3x=0
4x+4y+2x=0
6x+4y=0
6x=-4y
x=-2y/3

Remplazamos x:
√16(-2y/3)^2+√16y^2+5(-2y/3)-3(-2y/3)=0
4(-2y/3)+4y-10y/3+2y=0
-8y/3-10y/3+6y=0
-18y/3+6y=0
-6y+6y=0
0=0

No pertenece....