Question

Identidades trigonométricas URGENTEEEEE:
1)CSCX/SECX=COTX
2)COS´2x(SEC´2X-1)=SEN´2X

Answer 1

1)

csc x / sec x = cot x
( 1 / sen x ) / ( 1 / cos x ) = cot x
cos x / sen x = cot x
cot x = cot x

2 )

cos² x ( sec² x - 1 ) = sen² x
cos² x ( ( 1 / cos² x ) - 1 ) = sen² x
cos² x ( 1 - cos² x ) / cos² x = sen² x
1 - cos² x = sen² x
sen² x = sen² x