Question

log2(x+3)-log2(2x-3)=1

Answer 1

$<var>\\\log_2(x+3)-\log_2(2x-3)=1 \\ \log_2\frac{x+3}{2x-3}=1\\ 2^1=\frac{x+3}{2x-3}\\ 2(2x-3)=x+3\\ 4x-6=x+3\\ 3x=9\\ x=3 </var>$