Question

√3-2i)³ calcular potencias

Answer 1

$( \sqrt{3} -2i)^3= \\ \\ ( \sqrt{3} -2i)( \sqrt{3} -2i)( \sqrt{3} -2i)= \\ \\ (3-2i \sqrt{3}-2i \sqrt{3}+4i^2)(\sqrt{3} -2i)= \\ \\ 3 \sqrt{3} -6i-6i+4i^2\sqrt{3}-6i+4i^2\sqrt{3}+4i^2\sqrt{3}-8i^3= \\ \\ 3 \sqrt{3}-18i+12i^2 \sqrt{3} -8i^3 \\ \\ Saludos$