Question

Si g(0)=-2, determina g^-1(-2)

Answer 1

g(0)=-2
x=0  entonce g=-2
ej.
g(x)=x-2
g(0)=0-2=-2

g(x)=x-2
x=g(x)+2
h(x)=x+2
h(x)=g⁻¹(x)=x+2
g⁻¹(x)=x+2
g⁻¹(-2)=(-2)+2=0