Question

hallemos......................

Answer 1

$\lim _{x\to \:2}\left(\frac{2x^2-1}{3x^3+5}\right)$
$\mathrm{Sustituir\:la\:variable}:$
$=\frac{2\cdot \:(2^2)-1}{3\cdot \:(2^3)+5}$
$=\frac{8-1}{24+5}$
$=\frac{7}{29}\quad \left(\mathrm{Decimal:\quad }\:0.24138\dots \right)$