Question

se agradece cualquier ayuda ​

Answer 1

Respuesta

a) P1 (-1,2)

b) P2 (-3,4)

Explicación paso a paso:

no se de esto sorry

Answer 2

Respuesta:

Explicación paso a paso:

1.

$\log _2\left(2x+4\right)=3\\\\2x+4=8\\\\x=2$

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4.

$\log _{10}\left(2\right)+\log _{10}\left(x+3\right)=\log _{10}\left(x+5\right)\\\\2\left(x+3\right)=x+5\\\\x=-1$

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5.

$\log _{10}\left(3\right)+\log _{10}\left(x-1\right)=\log _{10}\left(2\right)+\log _{10}\left(x+1\right)\\\\3\left(x-1\right)=2\left(x+1\right)\\\\x=5$

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3.

$x\log _{10}\left(3\right)+5=x\log _{10}\left(9\right)\\\\x\log _{10}\left(3\right)+5-5=x\log _{10}\left(9\right)-5\\\\x\log _{10}\left(3\right)=2\log _{10}\left(3\right)x-5\\\\x\log _{10}\left(3\right)-2\log _{10}\left(3\right)x=2\log _{10}\left(3\right)x-5-2\log _{10}\left(3\right)x\\\\-\log _{10}\left(3\right)x=-5\\\\\frac{-\log _{10}\left(3\right)x}{-\log _{10}\left(3\right)}=\frac{-5}{-\log _{10}\left(3\right)}\\\\x=\frac{5}{\log _{10}\left(3\right)}$

solo pude esas mano perdón:( corona si se puede ahi te deje el numero de cada una