Calcule el peso de 1 equivalente para las siguientes sustancias CaCl2, HNO3, Al(OH)3, Ca(OH)2 , H3PO4 , NaCl, LiOH.
Respuestas
Respuesta dada por:
27
CaCl2
Peq. = PM/ Nº valencia
PM = 110.98 g/mol
Peq. = 110.98 g/mol / 2 = 55.49 g/eq
HNO3
PM = 63 g/mol
Peq. = 63 g/mol / 1
Peq. = 63 g/eq
Al(OH)3
PM = 8 g/mol
Peq. = 78 g/mol / 3
Peq. = 26 g/eq.
Ca(OH)2
PM = 74 g/mol
Peq. = 74 g/mol / 2
Peq. = 37 g/eq.
H3PO4
PM =98 g/mol
PEq. = 98 g/mol /3
Peq. = 32.67 g/eq.
NaCl
PM = 58 g/mol
Peq. 0 58 g/mol / 1
Peq. = 58 g/eq.
LiOH
PM = 24 g/mol
Peq. = 24 g/mol 7 1 0 24 g/eq.
Peq. = PM/ Nº valencia
PM = 110.98 g/mol
Peq. = 110.98 g/mol / 2 = 55.49 g/eq
HNO3
PM = 63 g/mol
Peq. = 63 g/mol / 1
Peq. = 63 g/eq
Al(OH)3
PM = 8 g/mol
Peq. = 78 g/mol / 3
Peq. = 26 g/eq.
Ca(OH)2
PM = 74 g/mol
Peq. = 74 g/mol / 2
Peq. = 37 g/eq.
H3PO4
PM =98 g/mol
PEq. = 98 g/mol /3
Peq. = 32.67 g/eq.
NaCl
PM = 58 g/mol
Peq. 0 58 g/mol / 1
Peq. = 58 g/eq.
LiOH
PM = 24 g/mol
Peq. = 24 g/mol 7 1 0 24 g/eq.
Preguntas similares
hace 6 años
hace 6 años
hace 9 años
hace 9 años
hace 9 años