Question

P = 9•csc37º
Q = 25cos53º

Answer 1

Explicación paso a paso:

$p = 9. \csc( {37}^{o} ) \\ \csc( {37}^{o} ) = \frac{5}{3} \\ p = 9( \frac{5}{3} ) \\ p = 3(5) \\ p = 15$

$q = 25. \cos( {53}^{o} ) \\ \cos( {53}^{o} ) = \frac{3}{5} \\ q = 25( \frac{3}{5} ) \\ q = 5(3) \\ q = 15$