Question

el numero de moles en 10 L de CO2 a 20 grados centigrados y 800 torr.

Answer 1

P  x  V  = n(mol) x R x T

R= 0.0821 (L atm/mol K)

 1 Atm ------  760 torr
     x    ------    800 torr

x = 1.052 atm

T = 20 + 273 = 293 K

n =    P  x   V
     ``````````````
         R  x T


n =        1.052 atm  x  10 L
        ````````````````````````````````````
     0.0821 (L atm/mol K) x 293 K

n = 0.437 moles