Question

( x + 3) ( x+ 7 ) ayuda .. xf

( w + 12 ) ( w - 5 )

( x - 20 ) ( x + 6 )

( 3x + 5 ) ( 3x - 2 )

( 5y - 2 ) ( 5y + 6 )

( 2a + 5 ) ( 2a + 4 ) ​

Answer 1

Explicación paso a paso:

( x + 3 ) ( x + 7 ) = x²+ 7x + 3x + 21

= x²+10x+21

( w + 12 ) ( w - 5 ) = w² - 5w + 12w -60

= w²+7-60

( x - 20 ) ( x + 6 )= x² + 6x - 20x - 120

= x²-14x-120

( 3x + 5 ) ( 3x - 2 )= 9x² - 6x + 15x - 10

= 9x² + 9x -10

( 5y - 2 ) ( 5y + 6 )= 25y² + 30y - 10y - 12

= 25y² + 20y - 12

( 2a + 5 ) ( 2a + 4 )= 4a² + 8a + 10a +20

= 4a² + 18a +20

Espero te sirva :).