Question

3(11-9)-(4-3)-(10-2)

Answer 1

ΗΘΙΑ

procedimiento :

$3(11-9)-(4-3)-(10-2)$

$=3.2-(4-3)-(10-2)$

$=3.2-1-(10-2)$

$=3.2-1-8$

$=6-1-8$

$=-3$

salu2!!