Question

(n-19)(n-10)=

(x²+5)(x²+9)=

(a⁶+7)(a⁶-9)=

(x-4)(x-1)=

(x+3)(x-4)=


escrive x simple inspeccion​

Answer 1

Respuesta:

• $(n-19)(n-10)=n^2-10n-19n+190=n^2-29n+190$
• $(x^2+5)(x^2+9)=x^4+9x^2+5x^2+45=x^4+14x^2+45$
• $(a^6+7)(a^6-9)=a^{12}-9a^6+7a^6-63=a^{12}-2a^6-63$
• $(x-4)(x-1)=x^2-x-4x+4=x^2-5x+4$
• $(x+3)(x-4)=x^2-4x+3x-12=x^2-x-12$