Question

12x / x^{2} -1[/tex]

Answer 1

$12x / x^{2} -1$

Dos posibles soluciones.

En el primer caso de que...

$\frac{12}{ {x}^{2} } - 1 = \frac{12}{x} - 1 = \frac{12 - x}{x}$

En el segundo caso de que...

$\frac{12 {x}^{2} }{ {x}^{2} - 1 } = \frac{12x}{(x + 1)(x - 1)} \\ \frac{a}{x + 1} + \frac{b}{x - 1} \\ 12x = a(x + 1) + b(x - 1) \\ 12x = x(a + b) + (a - b)$

$\binom{0 = a - b}{12 = a + b} \\ 12 = 2a \\ 6 = a$

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$0 = 6 - b \\6 = b$

$a = 6 \\ b = 6 \\ \frac{6}{x - 1} + \frac{6}{x + 1} respuesta$