Question

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Answer 1

Respuesta:

$396^0\times 1964-899+37+4^3=\\1\times \:1964-899+37+4^3\\=1\times \:1964-899+37+64\\=1964-899+37+64\\=1166$

$\sqrt{100}-\sqrt[3]{8}+\sqrt{64}-\sqrt{49}\\\sqrt{100}=10\\\sqrt[3]{8}=2\\\sqrt{64}= 8\\\sqrt{49} = 7\\=10-2+8-7\\=9$

$\sqrt{64}\div \sqrt{16}+\sqrt{81}\div \sqrt{9}-\sqrt{4}\\\\frac{\sqrt{64}}{\sqrt{16}}+\frac{\sqrt{81}}{\sqrt{9}}-\sqrt{4}\\2+3-2\\= 3$

$15-3\times 12\div 6+4^2\div 8\\=15-3\times \:12\div \:6+16\div \:8\\=15-6+16\div \:8\\=15-6+2\\=11$

$21+84\times 2-\left(36+49\right)+3^2\\=21+84\times \:2-85+3^2\\=21+84\times \:2-85+9\\=21+168-85+9\\=113$

$6^2\div \sqrt{\left(2^3+5^0\right)}+5^2\times \left(2^5-3^2\right)-4^3\\=2^2\times \:3-2^{11}\times \:5^2\times \:3^2\\12-460800\\=-460788$