Question

ayuda con el punto 2 porfa

Answer 1

$|g(x)-4|\ \textless \ 8(x-3)^2\\ \\ -8(x-3)^2\ \textless \ g(x)-4\ \textless \ 8(x-3)^2\\ \\ 4-8(x-3)^2\ \textless \ g(x)\ \textless \ 4+8(x-3)^2\\ \\ \texttt{Note que...}\\ \\ \lim\limits_{x\to3}4-8(x-3)^2=4=\lim\limits_{x\to3}4+8(x-3)^2\\ \\ \\ \\ \texttt{Por ende: }\lim\limits_{x\to3}g(x)=4$