necesito que me ayuden a resolver los siguientes quebrados de suma:
1+1+1=
2 4 8
(los numeros de abajo es el denominador)
3+1+5=
4 2 5
2+1+1=
3 4 6
1+2+1=
8 3 6
4+1+1=
5 3 6
nesecito las respuestas porfa
Respuestas
Respuesta dada por:
1
Tenemos:
1/2+1/4+1/8
=>1(4)+2(1)/2(4) +1/8
=>4+2/8 +1/8
=>6/8 +1/8
=>(6+1)/8
=>7/8
3/4+1/2+5/5
=>3(2)+4(1)/4(2) +1
=>6+4/8 +1
=>10/8+1
=>5/4+1/1
=>5(1)+4(1)/4(1)
=>5+4/4
=>9/4
2/3+1/4+1/6
=>2(4)+3(1)/3(4) +1/6
=>8+3/12 +1/6
=>11/12 +1/6
=>11(6)+12(1)/12(6)
=>66+12/72
=>78/72
=>13/12
1/8+2/3+1/6
=>1(3)+8(2)/8(3) +1/6
=>3+16/24 +1/6
=>19/24+1/6
=>19(6)+24(1)/24(6)
=>114+24/144
=>138/144
=>23/24
4/5+1/3+1/6
=>4(3)+5(1)/5(3) +1/6
=>12+5/15 +1/6
=>17/15+1/6
=>17(6)+15(1)/15(6)
=>102+15/90
=>117/90
=>13/10
1/2+1/4+1/8
=>1(4)+2(1)/2(4) +1/8
=>4+2/8 +1/8
=>6/8 +1/8
=>(6+1)/8
=>7/8
3/4+1/2+5/5
=>3(2)+4(1)/4(2) +1
=>6+4/8 +1
=>10/8+1
=>5/4+1/1
=>5(1)+4(1)/4(1)
=>5+4/4
=>9/4
2/3+1/4+1/6
=>2(4)+3(1)/3(4) +1/6
=>8+3/12 +1/6
=>11/12 +1/6
=>11(6)+12(1)/12(6)
=>66+12/72
=>78/72
=>13/12
1/8+2/3+1/6
=>1(3)+8(2)/8(3) +1/6
=>3+16/24 +1/6
=>19/24+1/6
=>19(6)+24(1)/24(6)
=>114+24/144
=>138/144
=>23/24
4/5+1/3+1/6
=>4(3)+5(1)/5(3) +1/6
=>12+5/15 +1/6
=>17/15+1/6
=>17(6)+15(1)/15(6)
=>102+15/90
=>117/90
=>13/10
Anónimo:
el resultado son las ultimas de cada uno
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