Question

\lim _{x\to 4}\:\frac{3x^2-8x-16}{2x^2-9x+4}

Answer 1

$\lim _{x\to 4}\left(\frac{3x^2-8x-16}{2x^2-9x+4}\right)$
Factorizar:
$=\frac{\left(x-4\right)\left(3x+4\right)}{\left(x-4\right)\left(2x-1\right)}$
$\mathrm{Eliminar\:los\:terminos\:comunes:}\:x-4$
$=\frac{3x+4}{2x-1}$
$\mathrm{Sustituir\:la\:variable}$
$=\frac{3\cdot \:4+4}{2\cdot \:4-1}$
$=\frac{16}{7}$