Question

P = 1/cot2x + 1/sec2x +1/csc2x​

Answer 1

$P \: = \: \frac{1}{cot(2x)} \: + \: \frac{1}{sec(2x)} \: + \: \frac{1}{csc(2x)}$

La solución es:

$\boxed{ \bold{P = \frac{sin(2x) \: + \: cos(2x)^{2} \: + \: cos(2x)sin(2x) }{cos(2x)} }}$

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