Question

hola como están me podrían ayudar porfas si no es mucha molestia​

Answer 1

Respuesta:

Explicación paso a paso:

6 )

$Radio: R= 12m$

$Angulo: \alpha =30$

$\pi =3.14$

Area del sector circular: $Asc = ?$

Fórmula:

$Asc = \frac{\pi R^{2}\alpha }{360}$

$Asc= \frac{\pi (12m)^{2}(30) }{360} =\frac{(3.14)(144m^{2} )(30)}{360} =\frac{13571.68m^{2} }{360 }$

$Asc= 37.7m^{2}$

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9 )

$Radio-mayor: R = 8cm$

$Radio-menor: r = 6cm$

$\pi =3.14$

Area de la corona circular: $Ac = ?$

$Formula:$

$A = \pi (R^{2} -r^{2} )$

$Ac = \pi ( 8^{2} -6^{2} ) = \pi ( 64-36) = \pi (28cm^{2} )$

$Ac = 28\pi cm^{2}$

$Ac = (3.14)(28cm^{2} )$

$Ac = 87.92cm^{2}$

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10 )

$Lado: a = 10m$

$Lado: b = 8cm$

$Lado: c = 6cm$

$\pi =3.14$

$Radio: R = ?$

Area sombreada: $As = ?$

Fórmula:

$R = \frac{b+c-a}{2} =\frac{8m+6m-10m}{2} = \frac{14m-10m}{2} =\frac{4m}{2}$

$R = 2m$

$As = \pi R^{2}$

$As = \pi (2m)^{2} = \pi (4m^{2} )$

$As = 4\pi m^{2}$

$As = (4)(3.14) m^{2}$

$As = 12.56m^{2}$