Question

necesito ayuda con estos 3 problemas con los pasos
por favor !!

Answer 1

Aquí en la imagen te dejo la resolución de los 3.

Answer 2

1) $-3-(1+ \frac{2}{4}- \frac{3}{8})/( \frac{2}{3}* \frac{1}{6}/ \frac{1}{2})$

1 + 2/4 - 3/8 (Comun denominador 16)

[16(1) + 4(2) - 2(3)]/16 = [16 + 8 - 6]/16 = 18/16 = 9/8

[(2/3)*(1/6)/(1/2)]

(1/6)/(1/2) = (2x1)/(6x1) = 2/6 = 1/3

Ahora (2/3)*(1/3) = 2/9

(9/8)/(2/9) = 81/16

- 3 - 81/16

- 48/16 - 81/16 = -129/16

2) $\frac{1^{-1}+2^{-2}+3^{-3}}{(1+2+3)^{-1}}$

(1 + 2 + 3)^(-1) = 6^(-1)

6^(-1) = 1/6

Ahora: 1^(-1) = 1

2^(-2) = 1/2² = 1/4

3^(-3) = 1/3³ = 1/27

1 + 1/4 + 1/27 = [108(1) + 27(1) + 4(1)]/(108) = (108 + 27 + 4)/108

139/108

Quedaria: (139/108)/(1/6) = (139x6)/(108x1) = 834/108 = 139/18

Rta: 139/18

3) (2/5)^(-2) + 1/(4^(-2)) + (2/7)^(-3) 

(2/5)^(-2) = 1/(2/5)^2 = 1/[4/25] = 25/4

1/(4^(-2)) = 1/(1/4²) = 4² = 16

(2/3)^(-3) = 1/(2/3)³ = 1/(8/343) = 343/8

(25/4) + 16 + (343/8)

Comun denominador 16

[4(25) + 16(16) + 2(343)]/16 = [100 + 256 + 686]/16 = 1042/16 = 521/8

Rta: 521/8