Calcular la fraccion molar de 12g de soluto (PM:34,5g/mol) Y 31 De Solvente (PM:70,1g/mol)
Ayudaaa pliss!!!
Respuestas
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n(mol)soluto = masa/Mm
n soluto = 12 g/ 34.5 g/mol = 0.347 mol
mol (solvente) = 31 g / 70.1 g/mol = 0.442 mol
mol total = n soluto + n svte
ntotal = 0.347 mol + 0.442 mol = 0.789 mol
Xsto = n sto
````````
n total
Xsto = 0.347 mol
``````````````
0.789 mol
Xsto = 0.44
Xsvte = 0.442 mol
``````````````````
0.789 mol
Xsvte= 0.56
Xsto + Xsvte = 1
0.44 + 0.56 = 1
n soluto = 12 g/ 34.5 g/mol = 0.347 mol
mol (solvente) = 31 g / 70.1 g/mol = 0.442 mol
mol total = n soluto + n svte
ntotal = 0.347 mol + 0.442 mol = 0.789 mol
Xsto = n sto
````````
n total
Xsto = 0.347 mol
``````````````
0.789 mol
Xsto = 0.44
Xsvte = 0.442 mol
``````````````````
0.789 mol
Xsvte= 0.56
Xsto + Xsvte = 1
0.44 + 0.56 = 1
johaanny:
Gracias por tu AYUDA!
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