Question

Calcular la fraccion molar de 12g de soluto (PM:34,5g/mol) Y 31 De Solvente (PM:70,1g/mol)
Ayudaaa pliss!!!

Answer 1

n(mol)soluto = masa/Mm
 n soluto = 12 g/ 34.5 g/mol = 0.347 mol

mol (solvente) = 31 g / 70.1 g/mol = 0.442 mol

mol total = n soluto + n svte

ntotal = 0.347 mol + 0.442 mol = 0.789 mol

Xsto =  n sto
           ````````
           n total

Xsto =  0.347 mol
           ``````````````
             0.789 mol

Xsto = 0.44

Xsvte =  0.442 mol
           ``````````````````
               0.789 mol

Xsvte= 0.56

Xsto + Xsvte = 1
0.44 + 0.56 = 1