Question

Ayudenme por favor es para un deber se los agradeseria mucho ​

Answer 1

Respuesta:

descarga Pthotomath ayuda muchísimo ♡

Answer 2

Respuesta:

Explicación paso a paso:

(1 - ∛-8) ^-1  - 0,3 - (10 ^-1 + $\frac{1}{10}$ )

= (1 - (-2))^-1 - $\frac{3}{10}$ - ($\frac{1}{10} + \frac{1}{10}$)

= (1 + 2)^-1 -$\frac{3}{10} - \frac{1}{5}$

= 3^-1 - $\frac{3}{10} - \frac{1}{5}$

= $\frac{1}{3}$ $-\frac{3}{10} - \frac{1}{5}$

=$-\frac{1}{6}$

$\sqrt{1-(\frac{5}{3} } )^{-2} +5^{-1} -0,9$

= $\sqrt{1-(\frac{3}{5} })^{2} +\frac{1}{5} -\frac{9}{10}$

=$\sqrt{1-\frac{9}{25} } +\frac{1}{5} -\frac{9}{10}$

=$\sqrt{\frac{16}{25} } -\frac{7}{10}$

=$\frac{4}{5} -\frac{7}{10}$

=$\frac{1}{10}$

$[(\frac{1}{3} )^{-1} +3^{-1} -\sqrt[3]{-27}-1,8]^{-1}$

= $(3+\frac{1}{3} -\sqrt[3]{-27}-1,8) ^{-1}$

=$(3+\frac{1}{3} -(-3)-1,8) ^{-1}$

=$(4,2 + \frac{1}{3})^{-1}$

=$(\frac{21}{5} +\frac{1}{5})^{-1}$

=$\frac{68}{15}^{-1}$

=$\frac{15}{68}$

$[(\frac{1}{3})^{-2} * 0,3^{-2} \sqrt[3]{\frac{1}{27} } ]^{-2}$

= $[3^{2} * (\frac{3}{10})^{-2} *\frac{1}{3} ]^{-2}$

= $[3^{2} * (\frac{10}{3})^{2} *\frac{1}{3} ]^{-2}$

= $[3^{2} * (\frac{10}{3})^{2} ]^{-2}$

= $(3 *\frac{100}{9} )^{-2}$

=$(\frac{100}{3} )^{-2}$

=$\frac{3}{100} ^{2}$

=$\frac{9}{10000}$

$[(\frac{3}{2} )^{-2} : (-\frac{2}{3} )^{4} ]:2,34$

= $[(\frac{3}{2}) ^{-2} : -\frac{2}{3} ^{4} ]:\frac{117}{50}$

= $[(\frac{3}{2}) ^{-2} :(\frac{3}{2} )^{-2} ] \frac{50}{117}$

= $\frac{3}{2} ^{2} * \frac{50}{117}$

= $\frac{9}{4} * \frac{50}{117}$

= $\frac{1}{2} * \frac{25}{13}$

= $\frac{25}{26}$