Question

(-243) exponente 0,6 + 1/27

Answer 1

Observación:

*  $N^\frac{a}{b} = \sqrt[b]{N^a}$

*  $0.6 = \frac{6}{10} = \frac{3}{5}$

Ahora, resolvamos el ejercicio:

$(-243)^{0.6} + 1/27 = (-243)^\frac{3}{5} + 1/27 \ \ (-243)^{0.6} + 1/27 = \sqrt[5]{-243^3} + 1/27 \ \ (-243)^{0.6} + 1/27 = \sqrt[5]{((-3)^5)^3} + 1/27 \ \ (-243)^{0.6} + 1/27 = (-3)^3 + 1/27 \ \ (-243)^{0.6} + 1/27 = -27 + 1/27 = -728/27 \approx -26.96$

Saludos!!