desarrolla los siguientes binomios (5+x)² (9m+4n)² (2a²x+6by²)² (8x²y+9m³)² (x+6)² (4x+7)² (4a²+6)² (5m+3)²
Respuestas
Respuesta:
(5+x)²=25+10x+x²
(9m+4n)²=81m²+72mn+16n²
(2a²x+6by²)²=4a⁴x²+24a²bxy²+36b²y⁴
(8x²y+9m³)²=64x⁴y²+144x²ym³+81m⁶
(x+6)²=x²+12x+36
(4x+7)²=16x²+56x+49
(4a²+6)²=16a⁴+48a²+36
(5m+3)²=25m²+30m+9
Explicación paso a paso:
Para resolver el binomio de una suma, se utiliza la siguiente ecuación:
(a+b)²=a²+2ab+b² .... De esta manera:
(5+x)²=(5)²+2·5·x+(x)²
(5+x)²=25+10x+x²
(9m+4n)²=(9m)²+2·9m·4n+(4n)²
(9m+4n)²=81m²+72mn+16n²
(2a²x+6by²)²=(2a²x)²+2·2a²x·6by²+(6by²)²
(2a²x+6by²)²=4a⁴x²+24a²bxy²+36b²y⁴
(8x²y+9m³)²=(8x²y)²+2·8x²y·9m³+(9m³)²
(8x²y+9m³)²=64x⁴y²+144x²ym³+81m⁶
(x+6)²=(x)²+2·x·6+(6)²
(x+6)²=x²+12x+36
(4x+7)²=(4x)²+2·4x·7+(7)²
(4x+7)²=16x²+56x+49
(4a²+6)²=(4a²)²+2·4a²·6+(6)²
(4a²+6)²=16a⁴+48a²+36
(5m+3)²=(5m)²+2·5m·3+(3)²
(5m+3)²=25m²+30m+9
Espero te sirva... жDaya Princeж