Respuestas
Respuesta:(-m - 1) • (1 - m)2
Explicación paso a paso:
Step by Step Solution
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Reformatting the input :
Changes made to your input should not affect the solution:
(1): "m3" was replaced by "m^3". 1 more similar replacement(s).
STEP
1
:
Checking for a perfect cube
1.1 -m3+m2+m-1 is not a perfect cube
Trying to factor by pulling out :
1.2 Factoring: -m3+m2+m-1
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: m-1
Group 2: -m3+m2
Pull out from each group separately :
Group 1: (m-1) • (1)
Group 2: (m-1) • (-m2)
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Add up the two groups :
(m-1) • (1-m2)
Which is the desired factorization
Trying to factor as a Difference of Squares:
1.3 Factoring: 1-m2
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 1 is the square of 1
Check : m2 is the square of m1
Factorization is : (1 + m) • (1 - m)
1.4 Rewrite (m-1) as (-1) • (1-m)
Multiplying Exponential Expressions:
1.5 Multiply (1-m) by (1-m)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (1-m) and the exponents are :
1 , as (1-m) is the same number as (1-m)1
and 1 , as (1-m) is the same number as (1-m)1
The product is therefore, (1-m)(1+1) = (1-m)2
Final result :
(-m - 1) • (1 - m)2