Question

calcula el valor x^2+2 de la siguiente igualdad 5(x-1)+16(2x+3)=3(2x-7)-x​

Answer 1

Respuesta:

5.(x-1)+16.(2x+3) = 3.(2x-7) -x

5x-5.1+16.2x+16.3 = 3.2x-3.7-x

5x-5+32x+48 = 6x-21-x

37x+43 = 5x-21

37x+43-5x = -21

32x+43 = -21

32x = -21-43

32x = -64

x = -64 : 32

x = -2

Comprobación:

5.(-2-1)+16.(2.-2+3) = 3.(2.-2-7)-2

5.-3+16.-1 = 3.(-4-7)-2

-15-16 = 3.-11-2

-31 = -33-2

-31 = -31

espero que te haya servido y espero q esté bien ":)