un gas ocupa un volumen de 520ml a 25°c y 650 mmHg de presion. calcula el volumen que ocuparia el gas a 700mmHg y °32c
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V1 = 520 mL / 1000 = 0.520 L
T1 = 25 + 273 = 298 K
P = 650 mmHg
1 atm --- 760 mmHg
x --- 650 mmHg
x = 0.85 atm
V2 = ?
T2 = 32 + 273 = 305 K
P = 700 mmHg
1 atm --- 760 mmHg
x --- 700 mmHg
x = 0.92 atm
V1 P1 T2 = V2 P2 T1
V2 = V1 P2 T2
``````````````
P2 T1
V2 = 0.520 L x 0.85 atm x 298 K
``````````````````````````````````````````
0.92 atm x 305 K
V2 = 0.496 L
V2 = 496 mL
T1 = 25 + 273 = 298 K
P = 650 mmHg
1 atm --- 760 mmHg
x --- 650 mmHg
x = 0.85 atm
V2 = ?
T2 = 32 + 273 = 305 K
P = 700 mmHg
1 atm --- 760 mmHg
x --- 700 mmHg
x = 0.92 atm
V1 P1 T2 = V2 P2 T1
V2 = V1 P2 T2
``````````````
P2 T1
V2 = 0.520 L x 0.85 atm x 298 K
``````````````````````````````````````````
0.92 atm x 305 K
V2 = 0.496 L
V2 = 496 mL
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