Question

Halla el valor de todas las razones trigonometrícas para el ángulo en cada triángulo​

Answer 1

Explicación paso a paso:

Teorema de Pitágoras

(Hipotenusa)² = (Cateto Opuesto)² + (Cateto Adyacente)²

c)

Hallamos c:      

c² = 4² + 4²

c² = 16 + 16

c² = 32  

c = √32  

c = 4√2

Razones trigonométricas

sen ∝ = 4/4√2 = 4√2/4√2√2=4√2/8 = √2/2

cos ∝ = 4/4√2 = 4√2/4√2√2=4√2/8 = √2/2  

tag ∝ = 4/4 = 1/    

cotan ∝ = 4/4 = 1/    

sec ∝ = 14√2/4 = 7√2/2

csc ∝ = 4√2/4 = 7√2/2

d)  

Hallamos a:      

7√2² = d² + d²

98 = d² + d

98 = 2d²

98/2 = d²  

49= d²  

√49 = d

7 = d  

Razones trigonométricas

sen ∝ = 7/7√2 =7√2/ 7√2√2 = 7√2/14 = √2/2

cos ∝ = 7/7√2=7√2/ 7√2√2 = 7√2/14 = √2/2  

tag ∝ = 7/7 = 1  

cotan ∝ = 7/7 = 1/  

sec ∝ = 7√2/7 = √2  

csc ∝ = 7√2/7 = √2