Question

resuelve la siguiente operación combinada​

Answer 1

Respuesta:

$4\frac{3}{10}$

Explicación paso a paso:

$\left(\frac{6}{7}+\frac{8}{14}\right)\left(\frac{6}{5}+\frac{3}{10}\right)+\left(\frac{6}{4}+\frac{4}{10}\right)\\\\=\left(\frac{6}{7}+\frac{4}{7}\right)\left(\frac{6}{5}+\frac{3}{10}\right)+\left(\frac{6}{4}+\frac{4}{10}\right)\\\\=\left(\frac{6}{7}+\frac{4}{7}\right)\left(\frac{6}{5}+\frac{3}{10}\right)+\left(\frac{3}{2}+\frac{4}{10}\right)\\\\=\left(\frac{6}{7}+\frac{4}{7}\right)\left(\frac{6}{5}+\frac{3}{10}\right)+(\frac{3}{2}+\frac{2}{5})\\\\\frac{6}{7}+\frac{4}{7}$

$\frac{6}{7}+\frac{4}{7}\\\\=\frac{6+4}{7}\\\\=\frac{10}{7}\\\\=\frac{10}{7}\left(\frac{6}{5}+\frac{3}{10}\right)+\left(\frac{3}{2}+\frac{2}{5}\right)\\\\\frac{6}{5}+\frac{3}{10}\\\\=\frac{12}{10}+\frac{3}{10}\\\\=\frac{12+3}{10}\\\\=\frac{15}{10} \\\\=\frac{3}{2}$

$=\frac{10}{7}\cdot \frac{3}{2}+\left(\frac{3}{2}+\frac{2}{5}\right)\\\\\frac{3}{2}+\frac{2}{5}\\\\=\frac{19}{10}\\\\=\frac{10}{7}\cdot \frac{3}{2}+\frac{19}{10}\\\\\frac{10}{7}\cdot \frac{3}{2}\\\\\frac{10}{7}\cdot \frac{3}{2}\\\\=\frac{2\cdot \:5\cdot \:3}{7\cdot \:2}\\\\=\frac{5\cdot \:3}{7}\\\\=\frac{15}{7}\\\\=\frac{15}{7}+\frac{19}{10}$

$=\frac{283}{70}\\\\=4\frac{3}{70}$