Question

derivada! f(x)=(2x-1)^3(3x^2-7)

Answer 1

f(x) = (2x-1)³ (3x²-7)

f'(x) = 3(2x-1)²(2)(3x²-7) + (2x-1)³(6x)

f'(x) = 6(3x²-7)(2x-1)² + 6x(2x-1)²

f'(x) = (2x-1)² [ 6(3x²-7)+1 ]

Answer 2

$f(x)= (2x-1)^{3}(3 x^{2} -7) \\ f'(x)=3(2x-1)^{2}(2)(3 x^{2} -7)+(2x-1)^{3} (6x) \\ f'(x)=6( 4x^{2}-4x+1)(3x^2-7)+6x(8x^3-12x^2+6x-1) \\ f'(x)=72x^4-72x^3-150x^2+168x-42+48x^4-72x^3+36x^2-6x \\ f'(x)=120x^4-144x^3-114x^2+162x-42$