Question

3x²-14x+8=0 por medio de formula general con todo y procedimiento

Answer 1

3X² - 14X + 8 = 0:  a = 3; b = -14; c = 8

$X=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$X=\frac{-(-14)\pm \sqrt{(-14)^2-4(3)(8)}}{2(3)}$

$X=\frac{14\pm \sqrt{196-96}}{6}$

$X=\frac{14\pm \sqrt{100}}{6}$

$X=\frac{14\pm \ {10}}{6}$

X1 = (14 + 10)/6 = 24/6 = 4

X1 = 4

X2 = (14 - 10)/6 = 4/6 = 2/3

X2 = 2/3