Question

1-4 ((3x-1 )/2-3(x-1)) = (3-2x)/9 cuanto es???

Answer 1

Respuesta:

1-4(3x-1) /2-3(x-1) = (3-2x)/9

-3(3x-1)/2-3(x-1) = (3-2x)/9

-9x+3/ 2-3x+3= (3-2x)/9

9(-9x+3)/5-3x = 3-2x

-81x+27 = (3-2x)(5-3x)

-81x+27 = 6x^2-19x+15

-81x+27-15 = 6x^2-19x+15-15

-81x+12 = 6x^2-19x

-81x+12+19x =6x^2-19x+19x

-62x+12 = 6x^2

-62x/2+12/2 = 6x^2/3

-31x+6 = 3x^2

-31x+6-3x^2 = 3x^2-3x^2

-31x+6-3x^2 = 0

-3x^2-31x+6 = 0

-(-3x^2-31x+6) = 0

3x^2+31x-6 = 0

X = -(31)+√((31)^2-4(3)(-6))/2×1

X = -31+-√(961+72)/2

X1 =( -31+-√1033)/2

X1 = (-31-√1033)/2

X2 = ( -31+√1033)/2