log (x+2) + log (x-1)=1
log3 (4x-5)=log3(2x+1)
2(3x-1)=256
Urgente

Respuestas

Respuesta dada por: jonpcj
0
log(x+2)+log(x-1) = 1

log(x+2)(x-1) = log10

(x+2)(x-1) = 10

(x+2)(x-1) - 10 = 0

x² + x - 12 = 0

(x + 4)(x - 3) = 0 ⇒ x=-4; x=3
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