Question

$\sqrt{121 + \sqrt{36 \times 3 {}^{2} } } + 5 {}^{1} - 2 {}^{2}$
​

Answer 1

Respuesta:

12.7898

Explicación paso a paso:

$\sqrt{121+\sqrt{36*3^{2} } }+5^{1}-2^{2}$

$\sqrt{121+\sqrt{6^{2} *3^{2} } }+5-(2)(2)$

$\sqrt{121+\sqrt{18^{2} } }+5-4$

$\sqrt{121+\sqrt{18^{2} } }+1$

$\sqrt{121+18 } }+1$

$\sqrt{139 } }+1$ = 12.7898 aproximadamente