Question

20kg hidroxido aurico transformar a mol y cuantas moles de oro hay

Answer 1

Mm Au(OH)3 =247,98 g/mol
n (mol)= masa /Mm

m = 20 x 1000 = 20000 g
n = 20000 g / 247.98 g/mol

n = 80.65 moles

Mm oro = 196,96 g/mol