Question

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Answer 1

Respuesta:

$(- 8abc + 22a {}^{2} - 18a) (2a) \\ (- 8abc + 22a {}^{2} - 18a) ( \frac{1}{2a} ) \\ \frac{ - 8abc}{2a} + \frac{22 {a}^{2} }{2a} - \frac{18a}{2a} \\ \frac{2a( 4bc)}{2a} + \frac{2a(11a)}{2a} - \frac{2a(9)}{2a} \\ \frac{ \cancel{2a}( 4bc)}{ \cancel{2a}} + \frac{ \cancel{2a}(11a)}{ \cancel{2a}} - \frac{ \cancel{2a}(9)}{ \cancel{2a}} \\ - 4bc + 11a - 9$

b)

$(18xyz + 24x {}^{2} yz) \div (3xyz) \\ \\ (18xyz + 24x {}^{2} yz)( \frac{1}{3xyz} ) \\ \\ \frac{18xyz}{3xyz} + \frac{24x {}^{2}yz }{3xyz} \\ \\ \frac{(3xyz)(6)}{3xyz} + \frac{(3xyz)(8x)}{3xyz} \\ \\ \frac{ \cancel{(3xyz)}(6)}{ \cancel{3xyz}} + \frac{ \cancel{(3xyz)}(8x)}{ \cancel{3xyz}} \\ 6 + 8x$

c)

$( - 10a {}^{2} {b}^{2} + 45a {}^{2} bc - 20abc) \div ( - 5ab) \\ ( - 10a {}^{2} {b}^{2} + 45a {}^{2} bc - 20abc)( \frac{1}{ - 5ab} ) \\ \\ \frac{ ( - 5ab)(2ab)}{ - 5ab} + \frac{( - 5ab)( - 9ac)}{ - 5ab} + \frac{ (- 5ab)(4c)}{ - 5ab} \\ \\ \frac{ \cancel{( - 5ab)}(2ab)}{ \cancel{ - 5ab}} + \frac{ \cancel{( - 5ab)}( - 9ac)}{ \cancel{- 5ab}} + \frac{\cancel{ (- 5ab)}(4c)}{ \cancel{- 5ab}} \\ 2ab - 9ac + 4c$

d)

$(4x {}^{2} {y}^{2} {z}^{2} - 40 {x}^{2} {y}^{2} z - 32x {y}^{2} {z}^{2} ) \div ( - 4xyz) \\ \\ (4x {}^{2} {y}^{2} {z}^{2} - 40 {x}^{2} {y}^{2} z - 32x {y}^{2} {z}^{2} ) ( \frac{1}{ - 4xyz} ) \\ \\ \frac{ ( - 4xyz)( - xyz)}{ - 4xyz} - \frac{(- 4xyz)( 10xy)}{- 4xyz} - \frac{(- 4xyz)(8yz)}{- 4xyz} \\ \\ \\ \frac{\cancel{ ( - 4xyz)}( - xyz)}{\cancel{- 4xyz}} - \frac{\cancel{{(- 4xyz)}}( 10xy)}{\cancel{- 4xyz}} - \frac{ \cancel{(- 4xyz)}(8yz)}{\cancel{- 4xyz}} \\ - xyz + 10xy + 8yz$

e)

$(8a {}^{2} b + 12a {b}^{2} ) \div (10ab) \\ (8a {}^{2} b + 12a {b}^{2} )( \frac{1}{10ab} ) \\ \\ \frac{(2ab)(4a)}{(2ab)(5)} + \frac{(2ab)(6b)}{(2ab)5} \\ \\ \frac{ \cancel{(2ab)}(4a)}{\cancel{(2ab)}(5)} + \frac{\cancel{(2ab)}(6b)}{\cancel{(2ab)}5} \\ \\ \frac{4}{5} a + \frac{6}{5} b$

f)

$( - 14xyz {}^{2} + 15xy {}^{2} z {}^{2} - 18xyz) \div ( - 6xy) \\ \\ ( - 14xyz {}^{2} + 15xy {}^{2} z {}^{2} - 18xyz)( \frac{1}{ - 6xy} ) \\ \\ \frac{ ( xy)(14z {}^{2} )}{( xy)( - 6)} + \frac{( xy)(15 {z}^{2} y)}{(xy)( - 6)} - \frac{(xy)(18z)}{(xy)( - 6)} \\ \\ \frac{ \cancel{ ( xy)}(14z {}^{2} )}{\cancel{( xy)}( - 6)} + \frac{\cancel{( xy)}(15 {z}^{2} y)}{\cancel{(xy)}( - 6)} - \frac{\cancel{(xy)}(18z)}{\cancel{(xy)}( - 6)} \\ \\ \frac{7}{3} z {}^{2} + \frac{5}{2} y {z}^{2} + 3z$

g)

$(-2ab {}^{2} + 5ab {}^{2} ) \div ( \frac{1}{2} b) \\ (2ab {}^{2} + 5ab {}^{2} )( \frac{2}{b} ) \\ (3ab {}^{2}) ( \frac{2}{b} ) \\ (b)(3ab)( \frac{2}{b} ) \\ \\ \cancel{(b)}(6ab)( \frac{2}{ \cancel{b}} ) \\ 12ab$

h)

$(9xyz - 2xy) \div ( - \frac{3}{2} xy) \\ (9xyz - 2xy) ( - \frac{2}{3xy} ) \\ \frac{(9xyz)( - 2)}{3xy} - \frac{2xy(2)}{3xy} \\ \\ \frac{( \not9 {}^{3} \not x \not yz)( - 2)}{ \cancel{3xy}} - \frac{2 \not x \not y( - 2)}{3 \not x \not y} \\ \\ - 6z + \frac{4}{3}$

Espero que sea de tu ayuda

Saludos :)