Question

PORFAVOR AYUDENME CON ESTA TAREA

Determinar la masa molecular de los siguientes compuestos

1) HNO3
2) CO2
3) H3 PO4
4) HCL
5) ZN (CIO)2
6) CA (OH)2
7) C6 H12 O6
8) Bi (NO3)3
9) Be CO3
10) H2 Si O3

Answer 1

1. HNO3
H: 1 x1 = 1 g/mol
N: 1 x 14 = 14 g/mol
O= 3 x16 = 48 g /mol
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          Mm = 63 g/mol

2) CO2
c: 1 x 12 = 12 g7mol
O: 2 x 16 = 32 g/mol
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         Mm  =  44 g/mol.


3) H3 PO4
H: 1 x 1 = 3 g/mol
P: 1 x31 = 31 g/mol
O: 4 x 16 = 64 g/mol
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           Mm = 98 g/mol


4) HCl
h: 1 x 1 = 1 g/mol
Cl: 1 x 35.4 = 35.4 g/mol
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           Mm = 36.4 g/mol


5) Zn(CIO)2
Zn: 1 x 65.38 = 65.38 g/mol
Cl: 2 x 35.4 = 70.8 g/mol
O: 2 x 26 = 32 g/mol
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             Mm = 168.18 g/mol


6) Ca(OH)2
Ca: 1 x 40 0 40 g/mol
H: 2 x 1 = 2 g/mol
O: 2 x 16 = 32 g/mol
````````````````````````````````
         Mm = 74 g/mol


7) C6 H12 O6
C: 6 x 12 = 72 g/mol
H: 12 x 1 0 12 g/mol
O: 6 x 16 = 96 g/mol
``````````````````````````````
         Mm = 180 g/mol


8) Bi(NO3)3
Bi: 1 x 208,98 = 208,98 g/mol
N: 3 x 14 = 42 g/mol
O: 9 x 16 = 144 g/mol
``````````````````````````````````````
           Mm = 394.98 g/mol

9) BeCO3
Be = 1 x 9 = 9 g/mol
C: 1 x 12 = 12 g/mol
O: 3 x 16 = 48 g/mol
````````````````````````````````
           Mm = 69 g/mol


10) H2SiO3
H: 2 x 1 = 2 g/mol
Si: 1 x  28 = 28 g/mol
O= 3 x 16 = 48 g/mol
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           Mm = 78 g/mol