Question

si: 19ab + 18ab + 17ab + ... + 1ab =mxy77, determinar "a + x + y"

Answer 1

Respuesta:

19ab

+

18ab

+

17ab

+⋯+

1ab

=

xyz77

(1900+

ab

)+(1800+

ab

)+(1700+

ab

)+⋯+(100+

ab

)=

xyz77

100(19+18+17+⋯+1)+19×

ab

=

xyz77

19000+19×

ab

=

xyz77

===============

19×

ab

=...77→b=3

19×

a3

=...77

19(10a+3)=...77

190a+57=...77

190a=...20→a=8

1520=...20

===============

\begin{gathered}19000+19\times83 =\overline{xyz77}\\ \\20577=\overline{xyz77}\to x=2\\ \\a+x=8+2=10\end{gathered}

19000+19×83=

xyz77

20577=

xyz77

→x=2

a+x=8+2=10