Question

encuentre la distancia entre (4,-1) y (2,0)

Answer 1

Tenemos.

p₁(4, -1)
p₂(2 , 0)

Formula.

d² = (x₂ - x₁)² + (y₂ - y₁)²
d² = (2 - 4)² + (0 - (- 1))²
d² = (- 2)² + (0 + 1)²
d² = 4 + 1
d² = 5
d = √5

Respuesta.
d = √5

Answer 2

$d = \sqrt{ ( x_{2} - x_{1} )^{2} + ( y_{2} - y_{1} )^{2} }$

$d = \sqrt{ ( 2 - 4 )^{2} + [ 0 - (-1) ]^{2} }$

$d = \sqrt{ ( -2 )^{2} + [ 0 +1 ]^{2} }$

$d = \sqrt{ 4 + 1 }$

$d = \sqrt{ 5 }$

La distancia es $\sqrt{5}$